1919 Saxe-Weimar-Eisenach state election
German state election
The 1919 Saxe-Weimar-Eisenach state election was held on 9 March 1919 to elect the 42 members of the Landtag of Saxe-Weimar-Eisenach.[1]
Results
| Party | Votes | % | Seats | |
|---|---|---|---|---|
| Social Democratic Party of Germany | 72,730 | 40.35 | 16 | |
| German Democratic Party | 38,924 | 21.60 | 10 | |
| German National People's Party | 35,072 | 19.46 | 10 | |
| Independent Social Democratic Party of Germany | 18,411 | 10.22 | 5 | |
| German People's Party | 9,812 | 5.44 | 1 | |
| Centre Party | 5,284 | 2.93 | 0 | |
| Total | 180,233 | 100.00 | 42 | |
| Registered voters/turnout | 267,563 | – | ||
| Source: Elections in the Weimar Republic[1] | ||||
References
- ^ a b Gonschior, Andreas. "Der Freie Volksstaat S.-Weimar-Eisenach Landtagswahl 1919". Wahlen in der Weimarer Republik. Archived from the original on 2003-05-12. Retrieved 18 May 2021.
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- See also: Elections and referendums in Germany
- Elections in the Free State of Prussia
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